[linux] vypis suboru odkonca

[Andrej Neština]

Zdravim,

S tim perlom som si nejako neporadil :-|

Takze som stvoril nieco zlozitejsie ale funguje to:

bash-3.00# cat aa
# asd
/tmp/1 /tmp/a
# sss
/tmp/2 /tmp/b
/tmp/3 /tmp/c

bash-3.00# for x in `/usr/xpg4/bin/awk '!/^#/ {print $2}' aa` ; do echo
`grep $x aa |/usr/xpg4/bin/awk '{print $1,$2}'`; done
/tmp/1 /tmp/a
/tmp/2 /tmp/b
/tmp/3 /tmp/c
bash-3.00#

pouzitie volania systemu z awk som sa vyvaroval :-)

-----Original Message-----
From: linux-bounces na lists.linux.sk [mailto:linux-bounces na lists.linux.sk] On
Behalf Of Lubomir Host
Sent: Thursday, November 23, 2006 2:10 PM
To: Vseobecna diskusia o Linuxe
Subject: Re: [linux] vypis suboru odkonca

On Thu, Nov 23, 2006 at 12:26:55PM +0100, Andrej Neština wrote:
> Link s perlom mi funguje, dakujem
> Rajo mohol by si mi este poslat taky perl na unlink, dd.

To si uz dostudujes snad sam.

man perlfunc
vid popis funkcie unlink() ;-)

rajo

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